cj=:\@\ < cj (+/) a=:i.3 3 c +-----+-----+-------+ / \ |0 1 2|0 1 2|0 1 2| a1 a2 | |3 5 7|3 5 7| | | | | |9 12 15| x y +-----+-----+-------+ (<\)@(+/\) a (*/) cj (+/) a +-----+-----+-------+ 0 1 2 |0 1 2|0 1 2|0 1 2| 0 5 14 | |3 5 7|3 5 7| 0 60 210 | | |9 12 15| +-----+-----+-------+定義連接詞的明確 form,如在Section 18 的練習,可以產生如下所示之類似的連接詞 CJ。 相對應的 tacit 定義由 12 : s 得到:
s=: 0 : 0 (x.\)@(y.\) ) CJ=: 2 : s (*/) CJ (+/) a 0 1 2 0 5 14 0 60 210 12 : s \ @ \
練習
24.1 | Use display of 12 : s as a guide in defining an equivalent 連接詞 C ,and compare resulting 定義with simpler 定義 used for cj . |